Question

distance between points -5,-4 and 2, -1 on coordinate plane

Answer 1

$\underline{\textbf{Given:}}$

$\textsf{Points are (-5,-4) and (2,-1)}$

$\underline{\textbf{To find:}}$

$\textsf{The distance between the given two points}$

$\underline{\textbf{Solution:}}$

$\underline{\textsf{Distance formula:}}$

$\mathsf{The\;distance\;between\;(x_1,y_1)\;and\;(x_2,y_2)\;is}$

$\boxed{\mathsf{d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}}$

$\underline{\textsf{Distance between the points (-5,-4) and (2,-1)}}$

$\mathsf{=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}$

$\mathsf{=\sqrt{(-5-2)^2+(-4+1)^2}}$

$\mathsf{=\sqrt{(-7)^2+(-3)^2}}$

$\mathsf{=\sqrt{49+9}}$

$\mathsf{=\sqrt{58}\;units}$

$\therefore\mathsf{The\;distance\;between\;the\;given\;points\;is\;\sqrt{58}\;units}$

$\underline{\textbf{Find more:}}$

P(5,-3) and Q(-7,y) and PQ=13 units, find y​  

https://brainly.in/question/15041779

Answer 2

SOLUTION

TO DETERMINE

The distance between points (-5,-4) and (2, -1) on coordinate plane

CONCEPT TO BE IMPLEMENTED

For the given two points $\sf{A( x_1 , y_1) \: \: and \: \: B( x_2 , y_2)}$ the distance between the points

$= \sf{ \sqrt{ {(x_2 -x_1 )}^{2} + {(y_2 -y_1 )}^{2} } }$

EVALUATION

Here the given points are (-5,-4) and (2, -1)

So the required distance between the given points

$\sf{ = \sqrt{ {( - 5 - 2)}^{2} + {( - 4 + 1)}^{2} } \: \: \: unit }$

$\sf{ = \sqrt{ {( - 7)}^{2} + {( - 3)}^{2} } \: \: \: unit }$

$\sf{ = \sqrt{ 49 + 9 } \: \: \: unit }$

$\sf{ = \sqrt{ 58} \: \: \: unit }$

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