distance between points (-5,5/8) and (5, 5/8)
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Answered by
2
let the A(-5,5/8)
andB(5,5/8)
(AB)^2=(x1-x2)^2+(y1-y2)^2
=(-5-5)^2+(5/8-5/8)^2
AB=ROOT 100
=10unit
andB(5,5/8)
(AB)^2=(x1-x2)^2+(y1-y2)^2
=(-5-5)^2+(5/8-5/8)^2
AB=ROOT 100
=10unit
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Answered by
4
Distance = √ [ (y2-y1)² + (x2 - x1)² ]
Find the distance by using the formula:
Distance = √ [ 5/8 - 5/8)² + (5 - (-5) ) ² ]
Distance = √ [ 0 +10² ]
Distance = √ 100
Distance = 10 units
Answer: The distance between the two is 10 units
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