distance between points (asin60 ,0) and (0,acos30) is
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Using distance formula
=√[(a sin60°-0)^2+(0-acos 30°)^2]
=√(3a^2/4+3a^2/4)
=a√(3/2) or a/2 (√6).
=√[(a sin60°-0)^2+(0-acos 30°)^2]
=√(3a^2/4+3a^2/4)
=a√(3/2) or a/2 (√6).
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Answer is attached...hope it helps..
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