Question

distance between poit (-4,5) and (12,p) is 10unit find the value of p​

Answer 1

Step-by-step explanation:

(x1,y1)=(-4,5) (x2,y2)=(12,p)

d=√(x2-x1)^2+(y2-y1)^2

10=√(12-[-4])^2+(p-5)^2

10=√(16)^2+(p-5)^2

10=√256+p^2-25

10=√231+p^2

10=15.19+p

p=10-15.19

p= -5.19