Question

distance between staion P & Q is 910 km . two person A &B start their journey from P&Q respectively in the morning 10 o'clock towards each other . the speed of B is 1/6 more than A . At the point of meeting , find the difference between the distance covered by them ?​

Answer 1

Answer:

Hoping so you will get it...

Answer 2

Step-by-step explanation:

given total distance = 910 km

let A covered X km

then B covered (910 - X) km

again let speed of A be V kmph

speed of B + V + V/6 = 7V/6 kmph

time taken by A in covering distance X

T = X/V

time taken by B in covering distance of 910-X km

T' = (910-X)/(7V/6)

= 6*(910-X)/7V

as per question T = T'

X/V = 6*(910-X)/7V

V gets cancelled both side

X = 6*(910-X)/7

7X = 6*910 - 6*X

7X + 6X = 6*910

13X = 6*910

X = 6*910/13

X = 420 km

distance covered by A = 420 km

distance covered by B = 910-X

= 910-420 = 490 km

difference between the distance covered

= 490-420

= 70 km