Question

Distance between the lines 15x+9y+14=0 and 10x+6y−14=0 is​

Answer 1

Step-by-step explanation:

First of all we have to find the value of x and y

so, from eq 10x+6y=14

=>x =(14-6y)/10

putting this value in eq 2

15x+9y+14=0

15((14-6y)/10)+9y+14jumping to third step

31-15y+9y+14 =0

45-6y=0

y=45/6

x=14-6y/10

x=14-45/10

x=-31/10

Answer 2

Answer:

15x+9y+14=0 (equation 1) and 10x+6y-14=0(equation 2) are the given equation

first we have to find these lines are parallel then only a distance exist between lines

for checking it's parallel condition is slopes are equal. m1=3/5 equ1 and m2=3/5 equ2 hence they are parallel

distance= |c1-c2|/√a^2-b^2

|7+14/3|/ √25+9 = 35/√34

answer is 35/√34