Question

Distance between the lines 3x+2y=6 and 3x+2y=12 is

Answer 1

Given:

The lines 3x+2y=6 and 3x+2y=12

To find:

Distance between the lines 3x+2y=6 and 3x+2y=12 is

Solution:

From given, we have,

The lines 3x + 2y = 6 and 3x + 2y = 12

Since the given lines are parallel, the formula used to find the distance between 2 parallel lines is given as follows,

d = |c1 - c2|/√[a² + b²]

so we have,

a = 3, b = 2, c1 = 6 and c2 = 12

substituting the above values in the equation, we get,

d = |6 - 12|/√[3² + 2²]

d = 6/√[9 + 4]

d = 6/√13

Therefore, the distance between the lines 3x+2y=6 and 3x+2y=12 is 6/√13