Question

distance between the lines 5x-12y+2=0 and 5x-12y-3=0 is

Answer 1

The distance between two parallel lines = perpendicular distance between these two.

 

The length of perpendicular drawn from a point in one line to another =  the distance between the two parallel lines. 

If

L1: y = mx + c11

L2: y = mx + c22


Then, the  formula for finding the distance between them is:

d = |c1−c2|/√1+m²

    L1: y = 5/12x + 1/6   L2: y = 5/12x – ¼     d = |1/6−(-1/4)|/√1+(5/12)²       = (5/12) / (13/12)   = 5/13

Answer 2

Answer:

Step-by-step explanation:

The distance between two parallel lines = perpendicular distance between these two.

The length of perpendicular drawn from a point in one line to another = the distance between the two parallel lines.

If

L1: y = mx + c11

L2: y = mx + c22

Then, the formula for finding the distance between them is:

d = |c1−c2|/√1+m²

L1: y = 5/12x + 1/6 L2: y = 5/12x – ¼ d = |1/6−(-1/4)|/√1+(5/12)² = (5/12) / (13/12) = 5/13