Question

Distance between the lines3x+4y-9=0 and 6x+8y-15= 0​

Answer 1

Answer:

Hence the distance between the lines 3x+4y=9,6x+8y=15 is 0.3.

Step-by-step explanation:

3x+4y=9,6x+8y+15=0

As can be seen from the slopes of the given lines, these two lines are parallel.

They can be written as 3x+4y=9 and 3x+4y=

2

−15

Therefore, the perpendicular distance between these lines is obtained by =

A

2

+B

2

C

1

−C

2

=

9+16

9+

2

15

=

5

2

33

=

10

33