Question

Distance between the parallel lines
5x-12y-3=0, 10x-24y+1=0 is *​

Answer 1

Step-by-step explanation:

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To find the distance between two parallel lines, plot the graphs on 1 graph paper and find it out.

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Answer 2

Answer: They are 7/26 units or about 0.26 units distant.

Explanation:

Let us make the coefficients of both the line equations same. (Coefficients of x, y.)

That is,

1. 2(5x - 12y - 3) = 2(0) = 10x - 24y - 6 = 0
2. 10x - 24y + 1 = 0

Now we know, distance b/w two // lines:

$d = \dfrac{| C_1 - C_2 |}{\sqrt{A^2 + B^2}}$

So,

d = |- 6 - 1|/[√(10² + (- 24²)]

=> d = |-7|/(√676) = 7/26 units.