Question

Distance between the plates of a parallel plate
capacitor is 'd' and area of each plate is A. When
a slab of dielectric constant K and thickness tis
placed between the plates, its capacity becomes
CP0019
E A
&A
(1)
(2
1
t 1
d+til+
1
K
܀
K
EA
E A
(3)
(4)
1
1
d-t1+
d-t1
K
K
CP0020​

Answer 1

Explanation:

ANSWER

Capacitance of parallel plate capacitor is C=

d

Aϵ

If distance between plate is d/2

so new capacitance is C

′

=

d/2

Aϵ

=2

d

Aϵ

=2C