Question

Distance between the points (3,2) and (-1,4) is
(a)
$\sqrt[2]{5}$
(b)
$\sqrt[3]{5}$
(c)
$\sqrt{5}$
(d) None​

Answer 1

Step-by-step explanation:

$distance \: = \sqrt{( - 1 - 3) {}^{2} + (4 - 2) {}^{2} } \\ = \sqrt{( - 4) {}^{2} + (2) {}^{2} } \\ = \sqrt{16 + 4} \\ = \sqrt{20} \\ = 2 \sqrt{5} \: \: \: \: \: \: ans$

Answer 2

Answer:

$\huge{\boxed{\rm{\red{answer=2√5 units}}}}$

Step-by-step explanation:

Given:-

Given points are (3,2) and (-1,4)

To find:-

Distance between two points

Used formula:-

If (x1,y1) and (x2,y2) are two points then the distance between two points is √{(x2-x1)²+(y2-y1)²} units

Solution:-

Let (x1,y1)=(3,2)=>x1=3,y1=2

and (x2,y2)=(-1,4)=>x2=-1,y2=4

Distance=√{(-1-3)²+(4-2)²}

=>D=√{(-4)²+2²}

=>D=√(16+4)

=>D=√20 units

=>D=√(4×5)

=>D=2√5 units

Answer :-

The distance between two points is 2√5 units