distance between the points (7,4) and (3,y) is 4 units find the value of y..
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the formula is Square root of (y2-y1)square+ (x2-x1)square
i.e square root of (y-4)square+(3-7)square=4
y^2+16-8y+16=16
y^2-8y+16=0
by finding roots we get the value of y is 4
i.e square root of (y-4)square+(3-7)square=4
y^2+16-8y+16=16
y^2-8y+16=0
by finding roots we get the value of y is 4
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