Question

Distance between the points P(-1, 1) and
Q(5, - 7) ?​

Answer 1

Answer:

• The distance between the points is 10 units.

Step-by-step explanation:

As we know that,

Distance between two points = $\boldsymbol{\sqrt{(x_2-x_1)^2\;+\;(y_2-y_1)^2}}$

Given that,

• P(-1,1) and Q(5,-7)

❍ Let us conisder that,

• $\boldsymbol{x_1 = -1,y_1 = 1}$

• $\boldsymbol{x_2 = 5,y_2 = -7}$

Applying the values,

$:\implies\sf{PQ = \sqrt{\bigg(5-(-1)\bigg)^2 + \bigg((-7) - 1\bigg)^2}} \\ \\ \\ \implies\sf{PQ = \sqrt{\big(5+1\big)^2 + \big(-7-1\big)^2}} \\ \\ \\ :\implies\sf{PQ = \sqrt{\big(6\big)^2+\big(8\big)^2}}\\ \\ \\ :\implies\sf{PQ = \sqrt{36+64}}\\ \\ \\ :\implies\sf{PQ = \sqrt{100}}\\ \\ \\ :\implies\sf{PQ = 10 \;units}$

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