Distance between two masses is reduced to half. What is The % change in their mutual gravitational force?
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the force is quadrupled. hence the Percentage change is 300% increased
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Given:
Two masses under mutual gravitational force separated by some distance
To Find:
The percentage change in their mutual gravitational force if the distance is reduced to half
Solution:
The gravitational force F between two bodies of masses M and m kept at a distance d from each other is given by
F = G m M / d² - (1)
Where,
G is the gravitational constant and has the value 6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²
Given that the distance is reduced to half then,
d → d / 2
The new gravitational force F' = - (2)
= 4 G m M / d
From equations 1 and 2, we can say that
F' = 4 X F
The percentage change = (New Value - Initial Value) X 100/ Initial Value
= (F' - F )X 100/ F
= (4F - F) X100 / F
= 300%
Hence, the percentage increase in their mutual gravitational force is 300%.
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