Distance between two places A and B is 120 km. Two cars start simultaneously from A and B in opposite direction and distance between them after 3 hours is 54 km. If speed of one car is less than that of other by 8 km/hr. Find the speed of each.
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Let speed of 1st car be x km/hr
speed of 2nd car=(x-8)km/hr
t=3 hr
distance travelled by car1 in 3 hrs=3*x km
distance travelled by car2 in 3 hrs=3*(x-8) km
distance between two cars after 3 hrs= 54 km
120-[3x+3x-24]=54
120-54=6x-24
66+24=6x
6x=90
x=90/6
x=15
speed of 1st car =15 km/hr
speed of 2nd car =(15-8)km/hr =7 km/hr
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