Math, asked by raj8262888209, 10 months ago

distance between two points (5,7),(1,3)​

Answers

Answered by Mihir1001
42

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<font color="blue" size="5px"><b>Answer:</b></font>

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\huge\boxed{4 \sqrt{2}  units}

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<font color="red" size="5px"><b>Step-by-step-explaination:</b></font>

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let,

(x_1, y_1) = (5, 7)

(x_2, y_2) = (1,3)

Hence,

required distance

 =  \sqrt{ {(x_1 - x_2)}^{2}  +  {(y_1 - y_2)}^{2} }

 =  \sqrt{ {(5 - 1)}^{2}  +  {(7 - 3)}^{2} }

 =  \sqrt{ {(4)}^{2}  +  {(4)}^{2} }

 =  \sqrt{16 + 16}

 =  \sqrt{32}

 =  \sqrt{4 \times 4 \times 2}

 = 4 \sqrt{2}  \: units

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Answered by nhorsanglama
1

Answer:

hope it will help

Step-by-step explanation:

distance(d)=√(x₂-x₁)²+(y₂-y₁)²

d = √(1-5)²+ (3-7)²

d= √(-4) + (-4)²

d = √16+16

d = √32

d = √2×2×2×2×2

d = 2× 2 √2

d = 4√2 units

Therefore, distance(d) = 4√2 units

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