distance between two points ( 8 , -4 ) and ( 0 , a ) is 10. all the values are in the same unit of length. find the positive value of a
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chauhanisha2002:
the answer is 2 and not 10.
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LET A(8,-4) AND B(0,A)
AB=10 (SQUARING ON BOTH SIDE )
AB^2 =100
BY USING DISTANCE FORMULA
(0-8)^2 +(4+A)=100
64+16+A^2+8A=100
80+A^2+8A=100
A^2+8A-20=0
A^2-10A+2A-20=0
A(A-10)+2(A-10)=0
A=10
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