Question

Distance between two poles is 15 m. If there is a lamp on the bigger pole of height 12m, what will be the length of the shadow of the smaller pole of height 3m?​

Answer 1

Answer:

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Step-by-step explanation:

Let AB be the 1st pole and CD be the 2nd pole

AC=15m

CD=24m

let AB=x

CE=x

ED=24-x

consider triangle BED

tan30° = DE/BE

1/√3 = (24-x)/15

15= √3(24-x)

5√3 = 24-x

x = 24-5√3

= 15.33m