distance between two poles is 24 m distance line makes 60° with horizontal. How much is the pole longer than shorter pole?
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Step-by-step explanation:
Let the height of pole CD=h
then the height of the poleAB=2h
Now, the distance between the poles=60m
Let X be the mid-point of BD
Let ∠DXC=θ,∠BXA=90
∘
−θ
Now, in △CDX
tanθ=
DX
CD
=
30
h
......(1)
In △ABX
tan(90
∘
−θ)=cotθ=
BDX
AB
=
30
2h
......(2)
⇒tanθ×cotθ=
30
h
×
30
2h
⇒1=
450
h
2
⇒h=15
2m
So, height of smaller pole=15
2m
Height of bigger pole=30
2m
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