Math, asked by Pariksweety, 4 months ago

distance between two stations P and Q is 1200 kilometre the two cars start simultaneously from P and Q respectively towards each other and then the distance between them after 5 hours is 100 kilometre if the speed of the car A is less than the other car by 20 kilometre per hour then find the
●Speed of car A
●Speed of car B
●Distance between cars A and B after 4hours
●average speed of both car
Please answer with explanation.

Answers

Answered by nehaliganvit3
1

Step-by-step explanation:

Let the trains start from station A and station B respectively.

Let the first train start from station A and the second train start from station B at the same time and move towards each other.

Let the speed of the first train be x km/hr

∴ the speed of the second train =(x+20) km/hr

Distance travelled by first train in 2 hours =2x km

Distance travelled by second train in 2 hours =2(x+20) km =(2x+40) km

Given, distance between two stations =300 km

According to the given condition, we have

Distance travelled by first train + Distance travelled by second train +20=300

i.e., 2x+(2x+40)+20=300

4x+60=300

4x=300−60 ....[Transposing 60 to RHS]

4x=240

Thus, x=

4

240

=60

∴ Speed of the first train =60 km/hr and

speed of the second train =(60+20) krn/h =80 km/hr.

Answered by ananyagarg2006
1

Answer:

100

speed of car a is 100K

speed of car b is 120 km

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