distance covered by a ball thrown upwards with speed U and last 30 seconds before it reaches maximum height is dash
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Answered by
0
Answer:
Let time of flight be T then T=
g
u
Let h be the distance covered during last 't' second of its ascent
Velocity at point B=V
B
=u−g(T−t)
=u−g(
g
u
−t)=gt
⇒h=V
B
t−
2
1
gt
2
⇒h=gt
2
−
2
1
gt
2
=
2
1
gt
2
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12
Answer:
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