Question

Distance covered by a freely falling body during the first three second of its motion A 10 m B 4.5 m C 40 m D 50 m​

Answer 1

Answer:

• 45 m is the required answer .

Explanation:

According to the Question

It is given that,

• Time taken ,t = 3s

we have to calculate distance covered by a freely falling body during the first three second of its motion.

Acceleration due to gravity is 10m/s².

So, here the initial velocity will be 0 m/s.

Now, using Kinematic Equation

• s = ut + ½ gt²

by substituting the value we get

⇢ s = 0 × 3 + ½ × 10 × 3²

⇢ s = 0 + 5 × 9

⇢ s = 45 m

• Hence, the distance covered by the body is 45 metres .

Answer 2

Explanation:

Answer:

45 m is the required answer .

Explanation:

According to the Question

It is given that,

Time taken ,t = 3s

we have to calculate distance covered by a freely falling body during the first three second of its motion.

Acceleration due to gravity is 10m/s².

So, here the initial velocity will be 0 m/s.

Now, using Kinematic Equation

s = ut + ½ gt²

by substituting the value we get

⇢ s = 0 × 3 + ½ × 10 × 3²

⇢ s = 0 + 5 × 9

⇢ s = 45 m

Hence, the distance covered by the body is 45 metres .

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