Question

distance covered by a freely falling body in 2 sec will be

Answer 1

From 3rd formula of law of motion, s=ut+1/2at^2

Explanation:

where,

u = 0 m/s^1

g = 9.8 m/s^2

t = 2 sec

s = o× 2 + 1/2×9.8×4

s = 1/2×9.8×4

s = 19.6m