Question

Distance covered by the particle is given by :-
S=(t3-6t2+3t+4)m. What is the velocity when its acceleration is zero?
Plz give answer

Answer 1

Step-by-step explanation:

s = t^3 _6t^2 + 3t +4

v is the derivative of s with respect to t

v = 3 t^2 _12t + 3 . To get v at the moment of 0 acceleration. We derive v again and substitute with o acceleration

a = 6t _12 , a= 0 when t = 2s

v = 3(2)^2 _12(2) + 3 , v= _9m/s. _ sign means that the direction of motion is backward