Question

distance formula A=(-5,0) B=(1,-3) c=(4,1) prove isosceles​

Answer 1

Answer:

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Answer 2

Vertices of the triangle are A(−3,0), B(1,−3), C(4,1).

Distance between two points =

(

x

2

−x

1

)

2

+(y

2

−y

1

)

2

AB=

(1+3)

2

+(−3−0)

2

=5

BC=

(4−1)

2

+(1+3)

2

=5

AC=

(4+3)

2

+(1−0)

2

=5

2

AB=BC

Therefore, ΔABC is an isosceles triangle.

(AB)

2

+(BC)

2

=5

2

+5

2

=50

and (AC)

2

=(5

2

)

2

=50

∴(AB)

2

+(BC)

2

=(AC)

2

So, the triangle satisfies the Pythagoras theorem and hence it is a right angled triangle.