Question

distance in 3 hours?
A garrison of 120 men has provision for 30 days. At the end of five days, five more
men joined them. How many days can they sustain on the remaining provision?​

Answer 1

Step-by-step explanation:

more men less provision, less men more provision. men and days are indirectly proportional

so, m1d1=m2d2

120x30 = (120+5)d2

d2= 28.8 days

28.8-5=23.8 days

they can sustain for 23.8 days

Answer 2

Answer:

Let after the joining of 5 men (after 5 days), It took x days to sustain on the remaining provision then,

According to the question-

120×30=120×5+125×x

(120×30)−(120×5)=125x

120(30−5)=125x

120×25=125x

120=5x

x=24 days

Hence, this is the required answer.