distance in 3 hours?
A garrison of 120 men has provision for 30 days. At the end of five days, five more
men joined them. How many days can they sustain on the remaining provision?
Answers
Answered by
1
Step-by-step explanation:
more men less provision, less men more provision. men and days are indirectly proportional
so, m1d1=m2d2
120x30 = (120+5)d2
d2= 28.8 days
28.8-5=23.8 days
they can sustain for 23.8 days
Answered by
2
Answer:
Let after the joining of 5 men (after 5 days), It took x days to sustain on the remaining provision then,
According to the question-
120×30=120×5+125×x
(120×30)−(120×5)=125x
120(30−5)=125x
120×25=125x
120=5x
x=24 days
Hence, this is the required answer.
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