Physics, asked by Pujithachinni1435, 1 year ago

Distance is always equal to displacement or greater than displacement. explain ?

Answers

Answered by SHADED
9

Distance is always greater than displacement because displacement is the shortest path from one point to another point,which is always straight but distance is the path which is longer than displacement but it is not always true  because  in some cases displacement is equal to the distance covered.This only happens when the  path taken is straight.

So by this we can conclude that,

                                                     distance ≥ displacement    

Attachments:

DayDreamer2943: Motta
SHADED: dei koodi-ya seekarathla neeyum poduva,kanadi
DayDreamer2943: Motta manda. Na contact lens poduvan ila laser surgery panuvan. Unaku wig matum dhaaaann
DayDreamer2943: Epd ? wig matum dhaan
SHADED: Apoo na vanthu hair replantation therapy pannuvan, poda
SHADED: machi enna than irunthalum nee koodiya seekarathala motta poduva athu kooda kanadiyum seathu poduva
DayDreamer2943: Dei athu already irukura mayira eduthu replace panuvanga . UNAKU DHAN ATHU KUDA ILAYA xDxDxD
DayDreamer2943: Athu cancel pantanada motta payala
Answered by ғɪɴɴвαłσℜ
3

\bigstarYes , distance is always greater than or equal to the displacement of an object

 \huge \sf Displacement

Displacement is the shortest distance between two points. And as we know the shortest distance between two points is always a straight line (this may not be applicable in the case of a larger distance because it is a globe and so the shortest distance is a curved line)

 \huge \sf Distance

Distance is the measure of the whole path covered by an object between any two points.

 \huge \sf{}Conclution

As we can see from the definition, the shortest path cannot be larger than the whole path travelled and if we tell that the statement is false the. it would be like telling that a part is greater than the whole. And sometimes the distance and the displacement can be the same when the distance travelled is also a straight line

That is :-

 \huge \boxed{ \red{ \fbox{ \pink{ \sf displacement \:  \leqslant distance}}}}

Similar questions