· Distance of a chord AB from the centre is 12 cmand length of the chord is 10 cm. then the diameterof the circle is
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Step-by-step explanation:
Let the attached circle be the required figure
Add point O and P as shown
Given - l (AB) = 10 cm chord
Figure - l (OP) = 12 cm distance
First we will find length of l (PB)
Therefore l (PB) = 1 / 2 x 10
= 5 cm
With the help of Pythagoras theorem
(hyp) square = (h) square + (b) square
= (12) square + (5) square
= 144 + 25
= 169
Hyp = root of 169 = 13 cm
Therefore OB = 13 cm
Diameter = 2 x r
= 26cm
Therefore diameter is 26cm
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