Question

Distance of chord AB from the center of a circle is 8 cm. Length of the chord AB is 12 cm. Find the diameter of the circle.
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Answer 1

Answer:

20 cm

Step-by-step explanation:

Given length of chord AB = 12 cm.

Distance of chord from center = 8 cm.

OC=8 cm .AC=

2

12

=6 cm

In △OAC

OA

2

=AC

2

+OC

2

OA

2

=(6)

2

+(8)

2

=36+64

[ OA=10 cm].

∴ Diameter of circle is 2(OA) = 20 cm.

Answer 2

${\large{\mathcal{\boxed{Answer}}}}$

Given length of chord AB = 12 cm.

Distance of chord from center = 8 cm.

OC=8 cm

$ac \: = \frac{12}{2 } = 6$

In triangle AOC ,

${oa}^{2} = {ac}^{2} + {oc}^{2}$

${oa}^{2} = {6}^{2} + {8}^{2} = 36 + 64$

( OA = 10cm )

• Diameter of Circle is 2(AO) = 20 cm