Question

distance of Chord ab from the centre is 12 cm and length of the chord is 10 cm find the diameter of the circle​

Answer 1

Answer:

r=Vd^2+ (c/2)^2 =v 12^2+5^2

=v169=13

radius=13cm

diameter = 2x13=26cm

Answer 2

The diameter of the circle​ is 26 cm.

Step-by-step explanation:

According to the given information ,

The distance of chord from center= OC= 12 cm .

A line drawn to represent this distance that makes right angle with the chord and divides it into two equal part each of AC = CB=5 cm .

( Shortest distance between the chord and center makes right angle and divides the chord into two equal parts.)

Join O and B , then Δ QCB would be a right triangle.

By Pythagoras theorem ,

$OB^2=OC^2+CB^2$

Put values of OC and CB

$OB^2=12^2+5^2$

$OB^2=144+25$

$OB^2=169$

$OB=13$

Since OB is radius of circle , then diameter of circle =2 (radius)= 2(13)=26 cm

Hence, the diameter of the circle​ =26 cm

#Learn more : Find the circumference of the circle diamter 2.5 m take pie 3.14

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