Question

distance of chord AB from the centre is 8 cm length of the chord AB is 12 cm find the diameter of the circle 8​

Answer 1

Step-by-step explanation:

According to question

AB=12cm

CD=8cm

Here

CDB is a Right angled triangle

in which

perpendicular=p=CD=8cm

Base=1/2AB=12/2=6cm

To find:-

Hypontenuse =radius =H

Solution:-

According to Pythagorean theory

${\boxed{{h}^{2}={p }^{2}+{b}^{2}}}$

${:}\longrightarrow$$h={\sqrt {{p}^{2}+{b}^{2}}}$

${:}\longrightarrow$$h={\sqrt {{8}^{2}+{6}^{2}}}$

${:}\longrightarrow$$h={\sqrt {64+36}}$

${:}\longrightarrow$$h={\sqrt {100}}$

${:}\longrightarrow$$h=10cm$

$\therefore$${\underline{\boxed{\bf {radius=10cm }}}}$