distance of chord AB from the centre of a circle is 8cm length of the chord AB is 12cm. find the radius of the circle.
pls give me the ans step by step from given to find and solution .
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1
Answer:
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Given length of chord AB = 12 cm.
Distance of chord from center = 8 cm.
OC=8 cm .AC= 2
12=6 cm
In△OAC OA 2 =AC 2+OC 2OA 2 =(6) 2 +(8) 2
=36+64
[ OA=10 cm].
∴ Diameter of circle is 2(OA) = 20 cm.
Answered by
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Step-by-step explanation:
perpendicular from centre to chord bisect the chord.
OM=8(given)
AM=1/2AB=6
in triangle OAM
AO^2=OM^2+AM^2
=8^2+6^2
=64+36
=100
so AO=10
radius 10
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