Question

Distance of point (2,5,7) from the x-axis is

Answer 1

Answer:

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Answer 2

Distance of point (2,5,7) from the x-axis is √74 unit

Given :

The point (2,5,7)

To find :

Distance of point (2,5,7) from the x-axis

Solution :

Step 1 of 3 :

Write down the given point

Here the given point is (2,5,7)

Step 2 of 3 :

Find foot of perpendicular from (2,5,7) on x-axis

The foot of perpendicular from (2,5,7) on x-axis (2,0,0)

Step 3 of 3 :

Find distance of point (2,5,7) from the x-axis

Hence the required distance

$\sf = \sqrt{ {(2 - 2)}^{2} + {(5 - 0)}^{2} + {(7 - 0)}^{2} } \: \: \: unit$

$\sf = \sqrt{ {(0)}^{2} + {(5)}^{2} + {(7 )}^{2} } \: \: \: unit$

$\sf = \sqrt{ 0 + 25 + 49} \: \: \: unit$

$\sf = \sqrt{ 74} \: \: \: unit$

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