distance of the chord ab from the centre of a circle is 8 cm length of a chord ab is 12 CM then find the diameter of a circle
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Ans: Diameter of circle is 20 cm
lukman51:
how??
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distance from chord = OC = 8cm
length of chord = AB = 12cm
In triangle OCA
angle C = 90°
AC = 6cm ( 12/2 cm)
OA = Radius =?
by Pythagoras
OA^2=OC^2+AC^2
OA^2 = (8)^2 + (6)^2
OA^2 = 64 + 36
OA^2 = 100
OA = 10 cm
radii = OA = OB = 10 cm
diameter = 20 cm
length of chord = AB = 12cm
In triangle OCA
angle C = 90°
AC = 6cm ( 12/2 cm)
OA = Radius =?
by Pythagoras
OA^2=OC^2+AC^2
OA^2 = (8)^2 + (6)^2
OA^2 = 64 + 36
OA^2 = 100
OA = 10 cm
radii = OA = OB = 10 cm
diameter = 20 cm
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