Distance of the perpendicular to the hypotenuse in a right angled triangle
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if u ar sskinh yes or no then yes
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Let the two sides containing right
angle be A and B
Then, hypotenuse=√(A2+B2)
Let the distance of perpendicular to
the hypotenuse be x
Now area of ∆=1/2AB=1/2x√(A^2+B^2)
=>x=AB/√(A^2+B^2)
=AB√(A^2+B^2)/(A^2+B^2)
Hope it helps
angle be A and B
Then, hypotenuse=√(A2+B2)
Let the distance of perpendicular to
the hypotenuse be x
Now area of ∆=1/2AB=1/2x√(A^2+B^2)
=>x=AB/√(A^2+B^2)
=AB√(A^2+B^2)/(A^2+B^2)
Hope it helps
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