Distance traveled by a free falling body at its 5th second of motion alone
Answers
Answered by
0
S = u + a/2 (2n-1)
n=5
u=0
S = 0+9.8 (2x5-1)
=9.8 (10-1)
=9.8 (9)
=88.2
n=5
u=0
S = 0+9.8 (2x5-1)
=9.8 (10-1)
=9.8 (9)
=88.2
Answered by
0
if a is not equal to b and if a2=5a -3 find the quadratic polynomial having zeroes a/b and b/a
Similar questions
Social Sciences,
9 months ago
Math,
9 months ago
Math,
9 months ago
Social Sciences,
1 year ago
English,
1 year ago
Environmental Sciences,
1 year ago