Science, asked by aah3moni1malsiralpa, 1 year ago

Distance traveled by a free falling body at its 5th second of motion alone

Answers

Answered by RaajM
0
S = u + a/2 (2n-1)

n=5

u=0

S = 0+9.8 (2x5-1)
=9.8 (10-1)
=9.8 (9)
=88.2
Answered by manasajulai
0
if a is not equal to b and if a2=5a -3 find the quadratic polynomial having zeroes a/b and b/a  
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