Question

Distance travelled by a train and time taken by it is shown in the following table.
a) Plot distance-time graph.
b) What is the average speed of the train?
c) When is the train travelling at the highest speed?
d) At what distance does the train slow down?
e) Calculate the speed of the train between 10.40AM to 11.00 AM.

Answer 1

Answer:

avg. speed= total distance/total time

=50/(1hour 50 minutes)

convert 1 hr 50 minutes into hour=

50 minutes= 5/6 hours so,

total time= 1+5/6=11/6 now

50/11/6= 50*6/11= 300/11

=27.27km/hr

train is traveling at the highest speed in first 30 minutes ( see in image) as the slope is highest in that time period and it's highest speed is 50km/hr

distance between 40 to 42 km the train slow down the most (see in graph)

distance covered between 10:40 to 11:00= length of CDE = cd + de= 12+2= 14

total time= 20 minutes= 1/3 hrs

speed= 14/1/3= 14*3= 42 km/hr

Explanation:

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Answer 2

Explanation:

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