Question

Distance travelled by particle starting from rest and moving with acceleration 4/3 m/s2 in 3 sec

Answer 1

Answer:

distance traveled = 6 m

Explanation:

initial velocity = u = 0 m/s

acceleration = a = 4/3 m/s^2

time = t = 3 sec

using equation of motion,

s = ut + (1/2) at^2

= 0 + (1/2) (4/3) 3×3

= 6

so, displacement = 6 m

_________________________

Hope, it helps you.