distinguish between by a chemical test
1) dil. H2SO4 & dil. HNO3
2) dil. H2SO4 & dil. HCl
3) dil. HCl & dil. HNO3
4) dil. H2SO4 & conc. H2SO4
5) dil. HNO3 & conc. HNO3
6) Na2SO3 solution & Na2CO3 solution
7) FeCl2 solution & FeCl3 solution
8) Pb(NO3)2 solution & Zn(NO3)2 solution
9) CuSO4 solution & ZnSO4 solution
10) Na2SO3 solution & Na2S2O3 solution
11) solid NaCl & solid NaNO3
12) NH4OH solution & NaOH solution
Answers
Answer:
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Class 12
>>Chemistry
>>The p-Block Elements
>>Sulphuric Acid
>>We can distinguish between solutions of
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Assertion
We can distinguish between solutions of dilute sulphuric acid with dilute HCl and dilute $$HNO_3$$.
Reason
With barium chloride solution sulphuric acid will give white precipitate while hydrochloric acid and nitric acid will not give any precipitate
Medium
Solution
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Correct option is A)
The reaction of barium chloride with dilute sulphuric acid forms white precipitate of barium sulphate and hydrochloric acid. This type of reaction is called double displacement reaction in which both the reactants exchange their partners.
BaCl2 (aq.)+ H2SO4 (aq.) ----- > BaSO4 (s) + 2HCl (aq.)
But when the barium chloride is treated with dilute nitric acid, all the reactants and products will be in aqueous state indicating that the complete solution will contain the ions of Ba+2 , Cl- , H+, NO3-
BaCl2 (aq.) + 2HNO3(aq.) ---- > Ba(NO3)2 (aq.) + 2HCl (aq.)
For a reaction to take place, either of the following conditions which must take place:
(a) the formation of insoluble product or precipitate.
(b) the evolution of gas.
(c) the formation of non-dissociating product.
Neither of these conditions is taking place on the reaction of barium chloride with dilute hydrochloric acid and nitric acid. hence, no reaction takes place in either of this case contrary to that of dilute sulphuric acid.
In case of reaction of barium chloride with dilute hydrochloric acid, the double displacement reaction cannot take place due to same anions with both the reactants.
BaCl2 (aq.)+ HCl (aq.) ----- > no reaction