Question

Distinguish between nuclear fission and fusion. In a fusion reaction, Calculate the amount of energy (in MeV) released. Given= 2.014102 u; = 3.016049 u; = 4.002603 u; = 1.00867 u; 1 u = 931.5 MeV/C2.

Answer 1

 Nuclear fission is the shifting of heavy nucleus into two lighter nuclei with the liberation of high amount of energy whereas nuclear fusion is the joining of two lighter nuclei to form one heavy nucleus with the liberation of high amount of energy.
 
(2.014102 u + 3.016049 u) → (4.002603 u + 1.00867 u) Mass lost = (2.014102 u + 3.016049 u) − (4.002603 u + 1.00867 u) m = 0.018878 u 1 u = 931.5 MeV/c2 Therefore, m = 0.018878 u = 0.018878 × 931.5 MeV/c2 E = mc2 = 0.018878 × 931.5 E = 17.58 MeV
Therefore, the amount of energy released is 17.58 MeV.

Answer 2

$\huge \fbox \colorbox{yellow}{ ♥ ANSWER ♥}$

• It is a shifting of heavy nucleus in to lighter muclei.