Distinguish between the following pair of substances :
(i) Hydrogen chloride and chlorine.
(ii) Sodium nitrate and sodium chloride.
(iii) Calcium chloride and Zinc chloride
(iv) Sulphuric acid and hydrochloric acid.
(v) Cupric ion and ferric ion.
Answers
Answer:
(1)Hydrogen chloride -Colour of gas: gas is greenish yellow.
Chlorine-Colour of gas: The gas is colourless.
(2)Sodium nitrate and sodium chloride.
To distinguish between sodium chloride solution and Sodium nitrate solution, you can use a silver nitrate test. When you add silver nitrate reagent to a solution containing sodium chloride, you will obtain a white precipitate of silver chloride.
(3) Calcium chloride and Zinc chloride
There are two ways to distinguish between calcium chloride and zinc chloride. Explanation: firstly we have to add traces of sodium hydroxide solution in both of the compound. Calcium chloride forms a curdy white PPT where is zinc chloride forms a gelatinous white precipitate.
(4) Sulphuric acid and hydrochloric acid.
With barium chloride solution sulphuric acid will give white precipitate while hydrochloric acid and nitric acid will not give any precipitate.
(5) Cupric ion and ferric ion.
Iron chloride solution -When NaOH solution is added a dirty green precipitate of iron (III) hydroxide is formed.
Copper chloride solution-When NaOH solution is added a bluish precipitate of copper (II) hydroxide is formed.
Answer:
Subtraction is not commutative because switching around the numbers in the operation yields a different solution. For example, because . The operations addition and multiplication are commutative, because no matter what order you place the numbers in, you will always get the same sum/product.
Explanation:
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