Distinguish between the following pairs of compounds using the test given within the bracket A compound contains 92.3 % carbon and rest hydrogen. Its molecular mass is 78. Calculate its molecular formula. (C=12, H = 1)
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Explanation:
Let the Empirical formula be CH
x
.
So,
12+x
12
×100=92.3⟹x=1
Empirical formula =CH
Empirical formula weight =13
Molecular weight = 2×39=78
EW
MW
=
13
78
=6
Molecular formula=(Empirical formula)
6
Thus, the molecular formula of the compound is C
6
H
6
.
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