Question

Distribute 632 among A,B and C in such a way that B will have 20% more than A and C has 20% less than A.​

Answer 1

Step-by-step explanation:

$let \: a \: has \: x \\ \\ therefore \: x \: + (x + 0.2x) + \\ ( x - 0.2x) = 632 \\ \\ \\ 3x = 632 \\ \\ x = 210.66$

$so \: a \: will \: have \: 210.66 \\ \\ b \: = 210 + 0.2 \times 210 \\ \\ 210.66 + 42.12 \\ \\ = 252.78 \\ c \: = 210.66 - 0.2 \times 210.6 \\ \\ 210.66 - 42.12 \\ \\ = 168.54$