Distribute electrons of chromium and copper on the basis of sub shell. Also mention the exceptional condition. Please give right answer.
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Answer:
Cr - [Ar] 4s1 4p5
Cu - [Ar] 4s1 4p10
Explanation:
Since chromium had 4 electrons, which is one short of 5 electrons to get just hslf-filled. ... To attain a completely filled electronic configuration copper gains one electron from the d-orbital and attains the electronic configuration of (Ar) d10 4s1. Thus both Cr and Cu have exceptional electronic configuration.
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