Question

Distribution of shear stress over a solid circular section

Answer 1

Hey Mate Heres the ans ;

LECTURE 19

Distribution of shear stresses in circular Shafts subjected to torsion :

The simple torsion equation is written as

This states that the shearing stress varies directly as the distance ‘r' from the axis of the shaft and the following is the stress distribution in the plane of cross section and also the complementary shearing stresses in an axial plane.

Hence the maximum strear stress occurs on the outer surface of the shaft where r = R

The value of maximum shearing stress in the solid circular shaft can be determined as

From the above relation, following conclusion can be drawn

(i) t maxm µ T

(ii) t maxm µ 1/d 3

HOPE IT HELPS YOU!!

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Answer 2

Answer:

Explanation:

It may be noted that the shear stress is distributed parabolically over a rectangular cross-section, it is maximum at y = 0 and is zero at the extreme ends. To get the maximum and minimum values of  substitute in the above relation. ... The maximum shear stress is at the neutral axis.