Question

ditance between the points (-2,3) (2,3)

Answer 1

Ello!

The distance between any two points whose cordinates are given can be calculated by the formula -

$d = \sqrt{{(x_{2} - x _{1})}^{2} + {(y _{2} - y _{1}) }^{2} }$


Here, the two points are A(-2,3) & B(2,3).

$ab = \sqrt{ {(2 + 2)}^{2} + {(3 - 3)}^{2} } \\ \\ ab = \sqrt{ {4}^{2} } \\ \\ ab = \sqrt{16} \\ \\ ab = 4 \: units$
Thus, AB is equal to 4 units!

✌️${Be } ^{Brainly }$✌️

Answer 2

         Distance Formula

By distance formula if A and B are two points on a coordinate plane such that:

A =====> ( x1 , y1 )

B =====> ( x2, y2 )

Then,

Distance between A and B is:

$\sqrt{ ( x2 - x1 )^2 + ( y2 - y1 )^2}$

Application of the formula

Given:

x1 = -2

x2 = 2

y1 = 3

y2 = 3

So the distance would be:

$\sqrt { ( 2 - ( -2 ))^2 + (3 - 3 )^2}$

$\implies \sqrt { (2+2)^2 + 0^2}$

$\implies \sqrt{ 4^2 + 0 }$

$\implies \sqrt{4^2}$

$\implies 4$

Hence the distance between these points is 4 units

Hope it helps you:-)

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