Question

Div. B = o. What do this differential
equation indicates?​

Answer 1

❏ GIVEN :

$\begin{gathered}\\\end{gathered}$

Area of the rhombus (a) = 225 cm²

Length of one diagonal (d) = 15 cm.

$\begin{gathered}\\\end{gathered}$

❏ TO FIND :

$\begin{gathered}\\\end{gathered}$

The length of the other diagonal.

$\begin{gathered}\\\end{gathered}$

❏ SOLUTION :

$\begin{gathered}\\\end{gathered}$

Suppose the other diagonal $\bf\red{=x }$

$\begin{gathered}\\\end{gathered}$

★══════════════════════★

✯ According to the formula :-

$\begin{gathered}\\\end{gathered}$

$\huge \color{blue}{\boxed{ \boxed{ \sf \color{blue}{A = \dfrac{1}{2} \times D \times x }}}}$

$\begin{gathered}\\\end{gathered}$

Where :

$\begin{gathered}\\\end{gathered}$

A = Area of the rhombus

D = Known diagonal of the rhombus

x = Unknown diagonal of the rhombus

$\begin{gathered}\\\end{gathered}$

➨Putting values :-

$\begin{gathered}\\\end{gathered}$

➨$\: \tt{225 = \dfrac{1}{2} \times 15x }$

➨ $\: \tt{225 = \dfrac{15x}{2} }$

➨ $\: \tt{225 \times 2 = 15x }$

➨$\: \tt{450 = 15x }$

➨$\: \tt{15x = 450 }$

➨$\: \tt{x = \dfrac{ \cancel{450}^{ \red{30}}}{ \cancel{15}{ \red{_1}}} }$

➥$\: \tt \pink{x = 30}$

$\begin{gathered}\\\end{gathered}$

∴ The length of the other diagonal = 30 cm.

$\begin{gathered}\\\end{gathered}$

❏ ANSWER :

$\begin{gathered}\\\end{gathered}$

The length of the other diagonal of the rhombus is 30 cm.

$\begin{gathered}\\\end{gathered}$

★══════════════════════★