divde 34 into two parts in such a way that 4/7.If one part is equal to 2/5 of the order.
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Let, the two numbers are x and (34 - x).
By the given condition,
4/7 × x = 2/5 × (34 - x)
⇒ 4x/7 = {2(34 - x)}/5
⇒ 5 × 4x = 7 × (68 - 2x)
⇒ 20x = 476 - 14x
⇒ 20x + 14x = 476
⇒ 34x = 476
⇒ 34x = 34 × 14
⇒ x = 14
∴ x = 14
So, the required numbers are
14 and (34 - 14)
i.e., 14 and 20.
#MarkAsBrainliest
Let, the two numbers are x and (34 - x).
By the given condition,
4/7 × x = 2/5 × (34 - x)
⇒ 4x/7 = {2(34 - x)}/5
⇒ 5 × 4x = 7 × (68 - 2x)
⇒ 20x = 476 - 14x
⇒ 20x + 14x = 476
⇒ 34x = 476
⇒ 34x = 34 × 14
⇒ x = 14
∴ x = 14
So, the required numbers are
14 and (34 - 14)
i.e., 14 and 20.
#MarkAsBrainliest
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