Question

divde 489 into 2 part such that 1 part is 9 more than twice the second part​

Answer 1

hey mate!! here is ur answer.....

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Answer 2

here is ur answer:

let one part b x

second part b 9 + 2x

ATQ-

$x + 9 + 2x = 489 \\ \\ 3x + 9 = 489 \\ \\ 3x = 489 - 9 \\ \\ 3x = 480 \\ \\ x = \frac{480}{3} \\ \\ x = 160 \\ \\ 2x + 9 = 160 \times 2 + 9 = 329$

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